JAVA_LeetCode 1854_Maximum Population Year 풀이 class Solution { public int maximumPopulation(int[][] logs) { // 년도(index), 횟수(value) 배열을 만들어서 최대횟수의 최소 인덱스를 출력한다. int[] cnt = new int[100]; int maxCnt = 0, year = 0; Arrays.fill(cnt, 0); for(int[] arr : logs){ for(int i = arr[0]; i < arr[1]; i++) cnt[(i - 1950)]++; } for(int i = 0; i < 100; i++){ if(cnt[i] > maxCnt){ maxCnt = cnt[i]; year = i + 1950; } } return year; } } * 출처 https://leetcode.com/problems/maximum-population-year...
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JAVA
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JAVA_LeetCode1854
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JAVA_LeetCode1854_MaximumPopulationYear
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JAVA_MaximumPopulationYear
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LeetCode1854_MaximumPopulationYear