JAVA_LeetCode 423_Reconstruct Original Digits from English 풀이 class Solution { public String originalDigits(String s) { int[] count = new int[26]; int[] digits = new int[10]; for(char ch : s.toCharArray()) count[ch - 'a']++; digits[0] = count['z' - 'a']; // zero digits[2] = count['w' - 'a']; // two digits[4] = count['u' - 'a']; // four digits[6] = count['x' - 'a']; // six digits[8] = count['g' - 'a']; // eight digits[1] = count['o' - 'a'] - digits[0] - digits[2] - digits[4]; // one digits[3] = c...
